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объясните пожалуйста как решать 111p^8q^-10* (1/74)p^-5q^12 нужно упростить выражение.
(111 p^8 q^-10 )* ( (1/74)p^-5 q^12)= =(111/74)* (p^8 / p^5)* (q^12 / q^10)= =3/2 p^3 q^2. Ответ: 3/2 p^3 q^2.
otvet.mail.ru/question/85279330
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CR-10 GA-70 EC-80 Description Flex Focus Module Flex Dual Module Flex Cable Flex Focus Controller Flex Zoom Controller Flex Zoom Controller Focus Positional Servo Module Focus Positional Demand Zoom Demand Zoom Demand Zoom Servo Grip Clamper Grip Adapter Zoom Extension Cable (8P) CODE 1824A012 0002T071 1824A010 1824A024 1824A014.
www.canon.com/bctv/products/pdf/KT20x5B%20KRS1.pdf
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Wht's the source of the Qs? p^2 – 13p + 40 =(p-8)(p-5)=q For q to be <0, either (p-8) or (p-5) but not both should be negative. Only 6 and 7 satisfies this condition.
www.urch.com/forums/gmat-problem-solving/41562-probability-q.html
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gmatclub.com/forum/manhattan-gmat-probability-question-25178.html
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47% 50% 39% 45% 0% 0% 11% 1% Stable Increase 2% 3% Decrease sharply Decrease Increase rapidly Business activity April October Change Decrease sharply Decrease – q p q 13% q 13% p Stable 10% p 11% p 1% q Increase 3% p 8% p 5% q Increase rapidly 6% p 17% p 11% qp 1% 1% 0% Actual, over the past three months.
www.amcham.ru/AmCham%20Russia%20-%20Trend%20survey%2001-05-10_web.pdf
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www.ems.ma/images/D%C3%A9marrage%20agence%20de%20Bouskoura.pdf
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www.slideshare.net/reborn4papua/aljabar-presentation
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3,6 Z4,1,3 − Z4,2,7 Z4,1,2 P4 Alpha and s6,7 = det (Ω) s1,4 7/B1 P9 P6 P8 s1,6 = det (Q) s4,7 where P7 P4 P5 Q = −Z3,2,1 Z3,8,2 Ω − Z4,5
www.iri.upc.edu/download/scidoc/1335
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P2. q = p; P3. if (flag) P4. *p = 8; P5. *q = 4; } The assignment at P2 ensures p and q have the same guarded points-to relationships; thus p ∼ = q. The dereference of p at P4 cannot fail because the statement guard (the test on flag at P3) guarantees that p is non-null.
theory.stanford.edu/~aiken/publications/papers/pldi07a.pdf
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www.sec.gov/Archives/edgar/data/855931/000119312512203310/0001193125-12-203310.txt